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Where does the gate driver power go? Decoding the energy puzzle in MOSFET gate charging/discharging

2025/12/22

In MOSFET switching, the gate driver plays a critical role in charging and discharging the gate, and the underlying energy conversion process directly affects the efficiency and thermal design of the driver system. Although the conventional power loss equations are widely used, they can lead to misunderstandings in certain applications. This article re-examines the actual energy flow in driver circuits by analyzing several typical charging/discharging models, and further discusses the impact of parasitic inductance on system energy conservation, providing engineers with a more accurate basis for energy estimation and device selection.


1.Common Power Loss Calculation Equations for Driver Circuits

The driver charges the MOSFET as shown in Figure 1, and discharges it as shown in Figure 2:

2.jpg


Figure 1: Charging

1_1.jpg

Figure 2: Discharging

 

The power loss is calculated using the following equations:

image.png……(1)

image.png……(2)

Where:

QG is total gate charge at the end of charging.

fDRV is gate drive frequency.

VDRV is drive voltage.

QG*fDRV represents the average charging current.

VDRV*QG*fDRV represents the average power supplied by the source.

Equations (1) and (2) divide this power equally: half dissipated in the resistors and half stored in the capacitor. During discharge, the energy stored in the capacitor is dissipated through the resistor.

Clearly, the condition for equations (1) and (2) to hold is that the energy dissipated in the resistor equals the energy stored in the capacitor during charging. However, is this assumption always valid? Obviously not when the resistance is zero. What about when resistance is non-zero?


2. Constant Voltage Source Charging a MOSFET

The MOSFET charging waveform is shown in Figure 3, and the I-V curve in Figure 4.


3.jpg

Figure 3


4.jpg

Figure 4

Stage (1): The MOSFET is in the cutoff region, where the capacitance is CGATE= CGS+CGD.

Stage (2): The MOSFET is in the saturation region, where the capacitance is CGATE=CGS+CGD*(1+gm*RLOAD).

Stage (3): The MOSFET is in the saturation region, where the capacitance is CGATE=CGD*(1+ gm*RLOAD).

Stage (4): The MOSFET is in the linear region, where the capacitance is CGATE=CGS+CGD.

 

CGS and CGD can be found in the MOSFET datasheet, where CISS= CGS+CGD, CRSS= CGD.

Due to the Miller effect in the saturation region, CGD is amplified by a factor of (1+AV/V), where AV/V represents the amplification factor of the MOSFET in the saturation region.

CGD varies with voltage. For most MOSFETs, the following approximation formula applies:

ce7e571afe234df51bbc5357b5bd46d1.png……(6)

At stages (1), (2), and (4), CISS can be approximated as CGS in parallel with CGD_AVG. At Stage (3), VGS remains nearly constant, rendering CGS ineffective, and the driver charges CGD with a constant current.

(1) Power loss during constant-current charging in stage (3) of Figure 3


Energy dissipated in resistorimage.png

--10.png……(4)

Energy stored in capacitor image.png

--12.png     ……(5)

When VDRV-Vmiller=Vmiller, Vmiller=VDRV/2, the energy dissipated in the resistor equals the energy stored in the capacitor. When VDRV>2Vmiller, the resistor dissipates more energy than the capacitor stores. 

Energy supplied by the source ES=VDRV*IG*t=CGD*VDRV*VDS_off=ER+EC……(6)

(2) Power loss in RC charging (Stages (1), (2), and (4) of Figure 3 combined)

Let CG=CGS+CGD_AVG; voltage of CG at the end of charging UO=k*UDRV; charging duration is T; charging current is IG:

image.png

Energy stored in capacitor

image.png……(7)

Energy dissipated in resistor

image.png……(8)

--17.png, indicating that the energy stored in the capacitor is always less than the energy dissipated in the resistor. As the capacitor approaches full charge, the two values become closer.

Energy supplied by the source

--18.png……(9)


3.Capacitor Charging of MOSFET

In real-world circuits, when a driver IC charges the MOSFET, most of the charging current is supplied by a capacitor, allowing the driver circuit to be approximated as a model of capacitor-to-capacitor charging.

(1) Power loss during constant-current charging in stage (3) of Figure 3

Energy dissipated in resistor ER=CGD*VDS_off * (VDRV_AVG - Vmiller)

Energy stored in capacitor EC=CGD*Vmiller*VDS_off

Energy supplied by the source capacitor ES=CGD*VDRV_AVG*VDS_off=EC+ER

Compared to the formula for constant voltage source charging capacitor, VDRV is replaced by VDRV_AVG,

because the source capacitor voltage decreases during charging, so the average value over the charging process is used.


(2) Power Loss in RC Charging (Stages 1, 2, and 4 of Figure 3 Combined)

Let the initial voltage of the source capacitor CIN be UDRV, its instantaneous voltage be UIN; gate capacitance CG=CGS+CGD_AVG; voltage of CG at the end of charging UO=k*UDRV; charging duration is T; charging current is IG. As shown in Figure 5, voltage and current are solved using the s-domain model:

6.jpg

Figure 5

Let--23.png

--24.png

--25.png

After inverse Laplace transform:

--26.png

--27.png

--28.png

--29.png

Energy stored in capacitor

--30.png

Energy dissipated in resistor

--31.png……(11)

Energy supplied by the source capacitor

--32.png

When --33.png--34.png


meaning that the energy stored in the capacitor exceeds the energy dissipated in the resistor. 

When

--35.png, --36.png

meaning the resistor dissipates more energy than the capacitor stores.

--37.png

--38.png……(13)

Let--39.png--40.png……(14)


Assuming that at the end of charging, the voltages across the two capacitors are equal, charge conservation indicates:

--41.png , solving yiedls --42.png, substituting into Equation (14):

--43.png

Equation (15) shows that the energy supplied by the source capacitor exceeds the sum of the energy dissipated in the resistor and stored in the capacitor.

When --44.png, i.e., CG=CINthe denominator reaches its minimum, and the greater the difference between capacitance values, the smaller the energy loss.


4.Discharging of MOSFET

Let the initial capacitor voltage be UG, voltage at the end of discharging UO=kUG; discharge duration is T:

--45.png

--46.png

--47.png

Remaining energy stored in capacitor

--48.png

Energy dissipated in resistor

--49.png 

Initial energy stored in capacitor

--50.png

Therefore, during discharge, the energy released by the capacitor is entirely dissipated in the resistor.


5.Effect of Parasitic Inductance

The charging loop acts like a single-turn coil, introducing parasitic inductance. The model in Figure 6 more closely resembles real-world circuits.

5.jpg

Figure 6

In Stage (3) of Figure 3, which approximates constant-current charging, the effect of inductance is negligible and thus not analyzed.

Let the initial voltage of the source capacitor CIN be UDRV, and its instantaneous voltage be UIN; gate capacitance CG=CGS+CGD_AVG; voltage of CG at the end of charging UO=k*UDRV; charging duration is T; charging current is IG; parasitic inductance is L; --54.png

文件-56.png

--55.png

Since the time-domain expressions for IG and UO are extremely complex, T cannot be derived, nor can the resistor’s energy dissipation be calculated via formula. Since the resistor merely dissipates part of the energy, setting the resistance to zero simplifies the analysis, leaving only L and C in the circuit.

--56.png--57.png --58.png

After inverse Laplace transform:

--59.png

--60.png

--61.png

Energy stored in inductor at any time

--63.png     …… (16)

Energy stored in MOS capacitor at any time

--64.png  …… (17)

Energy stored in source capacitor at any time 

文件-66.png       …… (18)

Initial energy stored in source capacitor

--65.png

--67.png

                                    文件-69.png

--68.png……(19)

Equation (19) confirms energy conservation, with no additional energy loss. Of course, alternating electromagnetic fields will still radiate energy, but the presence of inductance suppresses the rate of current change.


6. Summary

Through quantitative analysis of the relationships among the energy dissipated in resistor, the energy stored in capacitor, and the energy supplied by the source under different charging models, this article demonstrates that the traditional assumption of “50-50 energy split” does not always hold. Particularly when the drive voltage exceeds twice the Miller level, energy dissipation in the gate resistor often exceeds the energy stored in the capacitor. In the capacitor-to-capacitor charging model, the energy distribution exhibits different characteristics. Additionally, during MOSFET turn-off, all stored energy is dissipated through the resistor, while parasitic inductance helps suppress energy loss to some extent. Understanding these energy paths is crucial for the precise design of high-efficiency gate driver systems, especially in high-frequency, high-density, and high-reliability power applications.


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